7:10 PM ET, August 29, 2013
Fenway Park, Boston, Massachusetts
Baltimore: Tillman (14-4, 3.66 ERA)
Boston: Lester (12-7, 3.97 ERA)
The Boston Red Sox are trying to impress their online sports betting fan by pulling away in the AL East race. They’re successfully distancing themselves from the sputtering Baltimore Orioles.
Boston will start with Jon Lester who will try to beat the O’s again as his club looks for their first sweep of the division rivals in over two years tonight at Fenway Park.
The Red Sox (79-55) own the best record in the AL and lead the East by 2 1/2 games on second-place Tampa Bay Rays. Boston and Tampa Bay seem to be separating themselves from the rest of the division, with third-place Orioles (70-61) 7 1/2 games out of first.
Baltimore is also 4 1/2 behind the Oakland Athletics for the AL’s second wild-card spot.
The Red Sox are able to claim responsibility for increasing the O’s deficits in those races. Boston opened this three-game series with a 13-2 thumping Monday before rallying for a 4-3 victory the following day.
Lester (12-7, 3.97 ERA) will try to help Boston complete their first sweep of Baltimore since taking all four meetings from July 7-10, 2011. The left-hander 15-2 with a 2.72 ERA in 23 career starts versus them, his highest victory total against any opponent.
The Washington native beat them most recently July 28, striking out eight while yielding four hits in seven innings of a 5-0 victory at Baltimore to re-establish his dominance. Lester had been 0-2 with a 4.80 ERA over the previous five matchups.
Baltimore’s pitchers aren’t likely to share that sentiment since they have a 4.77 ERA while dropping nine of 14.
However, YouWager experts consider Chris Tillman (14-4, 3.66) is doing his part with a 2.57 ERA over his last four starts, but he’s 0-1 in that span since he’s been backed by nine total runs.
The lineup let the 25 year-old down again Saturday, when he yielded one run and three hits with nine strikeouts in eight innings while not getting a decision in a 2-1 defeat to Oakland.